ALS-XZ: connect two almost locked sets
ALS-XZ uses two ALSs that share a restricted common candidate X: every X in one ALS sees every X in the other.
Key idea
The two sets cannot both use X freely, so another shared candidate Z must occur in at least one set. A cell seeing every Z occurrence can lose Z.
See the move, step by step
Connect two two-cell ALSs through candidate 6 and eliminate candidate 7.
Step 1 of 4
Find two nearby ALSs
Each highlighted pair has two cells and three distinct candidates.
Step 2 of 4
Identify X and Z
Candidate 6 is restricted common because all 6s across the sets see each other. Candidate 7 is the second shared digit.
Step 3 of 4
Find a peer of every Z
R3C6 sees the 7 at R1C6 through column 6 and the 7 at R3C8 through row 3, so its 7 is impossible.
Step 4 of 4
Keep both ALSs unresolved
Remove only candidate 7 from R3C6. The ALSs remain useful structures for later deductions.
Try it on today's puzzle
Prove the restricted common candidate first: every X in ALS A must see every X in ALS B. Then require the target to see every relevant Z.
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